3.2.27 \(\int \frac {1}{(a+b x^3)^{3/4} (c+d x^3)^{7/12}} \, dx\) [127]

Optimal. Leaf size=87 \[ \frac {x \left (\frac {c \left (a+b x^3\right )}{a \left (c+d x^3\right )}\right )^{3/4} \left (c+d x^3\right )^{5/12} \, _2F_1\left (\frac {1}{3},\frac {3}{4};\frac {4}{3};-\frac {(b c-a d) x^3}{a \left (c+d x^3\right )}\right )}{c \left (a+b x^3\right )^{3/4}} \]

[Out]

x*(c*(b*x^3+a)/a/(d*x^3+c))^(3/4)*(d*x^3+c)^(5/12)*hypergeom([1/3, 3/4],[4/3],-(-a*d+b*c)*x^3/a/(d*x^3+c))/c/(
b*x^3+a)^(3/4)

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Rubi [A]
time = 0.01, antiderivative size = 87, normalized size of antiderivative = 1.00, number of steps used = 1, number of rules used = 1, integrand size = 23, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.043, Rules used = {388} \begin {gather*} \frac {x \left (c+d x^3\right )^{5/12} \left (\frac {c \left (a+b x^3\right )}{a \left (c+d x^3\right )}\right )^{3/4} \, _2F_1\left (\frac {1}{3},\frac {3}{4};\frac {4}{3};-\frac {(b c-a d) x^3}{a \left (d x^3+c\right )}\right )}{c \left (a+b x^3\right )^{3/4}} \end {gather*}

Antiderivative was successfully verified.

[In]

Int[1/((a + b*x^3)^(3/4)*(c + d*x^3)^(7/12)),x]

[Out]

(x*((c*(a + b*x^3))/(a*(c + d*x^3)))^(3/4)*(c + d*x^3)^(5/12)*Hypergeometric2F1[1/3, 3/4, 4/3, -(((b*c - a*d)*
x^3)/(a*(c + d*x^3)))])/(c*(a + b*x^3)^(3/4))

Rule 388

Int[((a_) + (b_.)*(x_)^(n_))^(p_)*((c_) + (d_.)*(x_)^(n_))^(q_), x_Symbol] :> Simp[x*((a + b*x^n)^p/(c*(c*((a
+ b*x^n)/(a*(c + d*x^n))))^p*(c + d*x^n)^(1/n + p)))*Hypergeometric2F1[1/n, -p, 1 + 1/n, (-(b*c - a*d))*(x^n/(
a*(c + d*x^n)))], x] /; FreeQ[{a, b, c, d, n, p, q}, x] && NeQ[b*c - a*d, 0] && EqQ[n*(p + q + 1) + 1, 0]

Rubi steps

\begin {align*} \int \frac {1}{\left (a+b x^3\right )^{3/4} \left (c+d x^3\right )^{7/12}} \, dx &=\frac {x \left (\frac {c \left (a+b x^3\right )}{a \left (c+d x^3\right )}\right )^{3/4} \left (c+d x^3\right )^{5/12} \, _2F_1\left (\frac {1}{3},\frac {3}{4};\frac {4}{3};-\frac {(b c-a d) x^3}{a \left (c+d x^3\right )}\right )}{c \left (a+b x^3\right )^{3/4}}\\ \end {align*}

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Mathematica [A]
time = 5.64, size = 86, normalized size = 0.99 \begin {gather*} \frac {x \left (1+\frac {b x^3}{a}\right )^{3/4} \sqrt [4]{1+\frac {d x^3}{c}} \, _2F_1\left (\frac {1}{3},\frac {3}{4};\frac {4}{3};\frac {(-b c+a d) x^3}{a \left (c+d x^3\right )}\right )}{\left (a+b x^3\right )^{3/4} \left (c+d x^3\right )^{7/12}} \end {gather*}

Warning: Unable to verify antiderivative.

[In]

Integrate[1/((a + b*x^3)^(3/4)*(c + d*x^3)^(7/12)),x]

[Out]

(x*(1 + (b*x^3)/a)^(3/4)*(1 + (d*x^3)/c)^(1/4)*Hypergeometric2F1[1/3, 3/4, 4/3, ((-(b*c) + a*d)*x^3)/(a*(c + d
*x^3))])/((a + b*x^3)^(3/4)*(c + d*x^3)^(7/12))

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Maple [F]
time = 0.07, size = 0, normalized size = 0.00 \[\int \frac {1}{\left (b \,x^{3}+a \right )^{\frac {3}{4}} \left (d \,x^{3}+c \right )^{\frac {7}{12}}}\, dx\]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(1/(b*x^3+a)^(3/4)/(d*x^3+c)^(7/12),x)

[Out]

int(1/(b*x^3+a)^(3/4)/(d*x^3+c)^(7/12),x)

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Maxima [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {Failed to integrate} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(1/(b*x^3+a)^(3/4)/(d*x^3+c)^(7/12),x, algorithm="maxima")

[Out]

integrate(1/((b*x^3 + a)^(3/4)*(d*x^3 + c)^(7/12)), x)

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Fricas [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {could not integrate} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(1/(b*x^3+a)^(3/4)/(d*x^3+c)^(7/12),x, algorithm="fricas")

[Out]

integral((b*x^3 + a)^(1/4)*(d*x^3 + c)^(5/12)/(b*d*x^6 + (b*c + a*d)*x^3 + a*c), x)

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Sympy [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \int \frac {1}{\left (a + b x^{3}\right )^{\frac {3}{4}} \left (c + d x^{3}\right )^{\frac {7}{12}}}\, dx \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(1/(b*x**3+a)**(3/4)/(d*x**3+c)**(7/12),x)

[Out]

Integral(1/((a + b*x**3)**(3/4)*(c + d*x**3)**(7/12)), x)

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Giac [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {could not integrate} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(1/(b*x^3+a)^(3/4)/(d*x^3+c)^(7/12),x, algorithm="giac")

[Out]

integrate(1/((b*x^3 + a)^(3/4)*(d*x^3 + c)^(7/12)), x)

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Mupad [F]
time = 0.00, size = -1, normalized size = -0.01 \begin {gather*} \int \frac {1}{{\left (b\,x^3+a\right )}^{3/4}\,{\left (d\,x^3+c\right )}^{7/12}} \,d x \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(1/((a + b*x^3)^(3/4)*(c + d*x^3)^(7/12)),x)

[Out]

int(1/((a + b*x^3)^(3/4)*(c + d*x^3)^(7/12)), x)

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